Steps to configure JSON View as a view resolver.
1) Create views.xml & put it into WEB-INF. Once you create a bean for jsonView it will automatically search for the views.xml file in WEB-INF folder.
<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE beans PUBLIC "-//SPRING//DTD BEAN 2.0//EN"
<beans>
<bean name="jsonView" class="org.springframework.web.servlet.view.json.JsonView">
<property name="jsonWriter">
<ref bean="jsonWriter" />
</property>
</bean>
<bean name="jsonWriter"
class="org.springframework.web.servlet.view.json.writer.sojo.SojoJsonStringWriter">
<property name="keepValueTypesMode">
<value>ALL</value>
</property>
</bean>
</beans>
2) Creating bean’s for view resolver such as the application should support more than one view.
<bean id="resourceViewResolver"
class="org.springframework.web.servlet.view.ResourceBundleViewResolver">
<property name="basename" value="views" />
<property name="order" value="2" />
</bean>
<bean id="xmlViewResolver"
class="org.springframework.web.servlet.view.XmlViewResolver">
<property name="order" value="1" />
</bean>
Generally we use to write view resolver bean configuration in servler.xml.
Observe the order attribute for above bean. We have configure to view resolver here.
3) Returning jsonView as a view from Spring Controller.
JSONObject jsonObject = new JSONObject();
jsonObject.put("success", true);
return new ModelAndView("jsonView", jsonObject);
4) You can check JSON response in firebug.
5) Required libraries :-
Jquery, extjs, YUI, etc library supports for the JSON.
e.g. We can bind JSON data coming from server directly to the table provided by javascript lib.
-/ Dinesh

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